Linuks
Mene pisit privet rank 2   Dikhil, Djibouti
 
 
● ∫ √(x2 + a2).dx =1/2.x.√(x2 + a2)+ a2/2 . log|x + √(x2 + a2)| + C
● ∫1/(x2 + a2).dx = 1/a.tan-1x/a + C
● ∫1/√(x2- a2)dx = log|x +√(x2- a2)| + C
● ∫ √(x2- a2).dx =1/2.x.√(x2- a2)-a2/2 log|x + √(x2- a2)| + C
● ∫1/√(a2- x2).dx = sin-1x/a + C
● ∫1/(x2- a2).dx = 1/2a.log|(x - a)(x + a| + C
● ∫ 1/(a2- x2).dx =1/2a.log|(a + x)(a - x)| + C
● ∫1/√(x2 + a2).dx = log|x + √(x2 + a2)| + C
● ∫√(a2- x2).dx = 1/2.x.√(a2- x2).dx + a2/2.sin-1 x/a + C
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