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Segnala un problema nella traduzione
Step2: Ctrl and F
Step3: Put 9 in
Step4: I hope you enjoy
1051541451431641621571721571511441234567881234567812345678123678326470547
2999999259923478990124999995689902993413269916749953349999914649932724997
2994567809912568990139956799809929936781467998299634699818991169966144990
2999994569970124995699801323459999012615302799995324993243699019923412993
2994567801993569980299356780239999456725634569974326992644399243992369936
2994567801992689901239967899029939945745315319931253399436998011992349950
2998012345299999388352999991039953991232012479934673289999982640499999415
It depends. If the selection is made WITHOUT REPLACEMENT, then the probability of the first can is 12% = 12 out of 100 = 6 out of 50 = 3/25. The probability of the 2nd can is then 5 out of 49 (assuming the first can is bad). We multiply the two separate probabilities to get the probability of the two events together: (3/25) * (5/49) = (3/245) = Answer "A".
But nothing says that the control worker couldn't make the selection WITH REPLACEMENT. If so, then the probability of the first can is 12/100, and the probabilty of the 2nd can is also 12/100. The two events together is (12/100) * (12/100) = (9/625) = Answer "C".