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Stefan-Boltzmann Equation
P = T^4
P = power in watts
T = the temperature of the object in kelvin
T = K^2
The surface temperature of particular object increases from 500K to 2000K. What effect does this have on the rate of transmission of thermal energy from the object
2000/500 = 4 = T
4^4 = 256 = P
The Stefan-Boltzmann relationship can be expressed by considering other variables in the rate of transfer of radiant energy
P = eoA T^4
P = power in watts
A = surface area in m^2
T = the temperature of the object in kelvin
O = the universal constant 5.67 * 10^-8 W m ^-2 K ^ -4
A black plastic water tank (e = .95) holds 1000 L of water at 90 C. The tank is a cube of 1 m length on each side. Estimate the rate of heat loss from the tank, assuming the surrounding environment is at 20 C
90 C = 363 K 20 C = 293
6 * 1 * 1 = 6m^2 SA for a cube
P = .95 * 5.67 * 10^-8 * 6 * (363^4 – 293^4) = 3230 W