Hey all, I'm stuck again, this time on Puzzle 39. The hint says that placing a 3 in r5c7 forces r6c2 and r6c5 to both be a 3 (which is obviously impossible, elimiminating 3 from r5c7), but I don't see how this happens. Placing a 3 in r5c7 seems to place a 3 in r6c2 and 2 in r6c5, even avoiding placing digits in those cells and following other clues as they unwind. I also can't see any other way to progress. Could anyone help me see what I'm missing? https://imgur.com/a/BfhLvsX...

Could someone help a thicky out? I managed to reach as far as the hints then guide, up to hint #4. I cannot fathom why 5 would be locked into r6 in box 4. It seems to me it could be in r5 or 6. Could someone tell me what I'm missing?

Solved for all 2 and 3, placed 4 in box 6 and box 9, penciled all other 4's... Hint #7 states 4 cannot go in R3C7, but in solved puzzle, this is exactly where it goes. At this point in the solve, it appears that either location for 4 in Box 3 is valid for all other penciled locations for 4. I'm seeking a LOGICAL step forward and not a leap of faith or luck... any assist on the logic gap closure is appreciated!...

Did anyone solve it?

As the title has described, we don't need the Thermo constraint and we can still solve it with a unique solution.